1.5x^2+1.5x=63

Solution for 1.5x^2+1.5x=63 equation:

1.5x^2+1.5x=63

We move all terms to the left:

1.5x^2+1.5x-(63)=0

a = 1.5; b = 1.5; c = -63;
Δ = b2-4ac
Δ = 1.52-4·1.5·(-63)
Δ = 380.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{380.25}}{2*1.5}=\frac{-1.5-\sqrt{380.25}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{380.25}}{2*1.5}=\frac{-1.5+\sqrt{380.25}}{3}
$